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5\left(3x^{3}+5x^{2}-2x\right)
Factor out 5.
x\left(3x^{2}+5x-2\right)
Consider 3x^{3}+5x^{2}-2x. Factor out x.
a+b=5 ab=3\left(-2\right)=-6
Consider 3x^{2}+5x-2. Factor the expression by grouping. First, the expression needs to be rewritten as 3x^{2}+ax+bx-2. To find a and b, set up a system to be solved.
-1,6 -2,3
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -6.
-1+6=5 -2+3=1
Calculate the sum for each pair.
a=-1 b=6
The solution is the pair that gives sum 5.
\left(3x^{2}-x\right)+\left(6x-2\right)
Rewrite 3x^{2}+5x-2 as \left(3x^{2}-x\right)+\left(6x-2\right).
x\left(3x-1\right)+2\left(3x-1\right)
Factor out x in the first and 2 in the second group.
\left(3x-1\right)\left(x+2\right)
Factor out common term 3x-1 by using distributive property.
5x\left(3x-1\right)\left(x+2\right)
Rewrite the complete factored expression.