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15x^{2}-82x+24=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-\left(-82\right)±\sqrt{\left(-82\right)^{2}-4\times 15\times 24}}{2\times 15}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-82\right)±\sqrt{6724-4\times 15\times 24}}{2\times 15}
Square -82.
x=\frac{-\left(-82\right)±\sqrt{6724-60\times 24}}{2\times 15}
Multiply -4 times 15.
x=\frac{-\left(-82\right)±\sqrt{6724-1440}}{2\times 15}
Multiply -60 times 24.
x=\frac{-\left(-82\right)±\sqrt{5284}}{2\times 15}
Add 6724 to -1440.
x=\frac{-\left(-82\right)±2\sqrt{1321}}{2\times 15}
Take the square root of 5284.
x=\frac{82±2\sqrt{1321}}{2\times 15}
The opposite of -82 is 82.
x=\frac{82±2\sqrt{1321}}{30}
Multiply 2 times 15.
x=\frac{2\sqrt{1321}+82}{30}
Now solve the equation x=\frac{82±2\sqrt{1321}}{30} when ± is plus. Add 82 to 2\sqrt{1321}.
x=\frac{\sqrt{1321}+41}{15}
Divide 82+2\sqrt{1321} by 30.
x=\frac{82-2\sqrt{1321}}{30}
Now solve the equation x=\frac{82±2\sqrt{1321}}{30} when ± is minus. Subtract 2\sqrt{1321} from 82.
x=\frac{41-\sqrt{1321}}{15}
Divide 82-2\sqrt{1321} by 30.
15x^{2}-82x+24=15\left(x-\frac{\sqrt{1321}+41}{15}\right)\left(x-\frac{41-\sqrt{1321}}{15}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{41+\sqrt{1321}}{15} for x_{1} and \frac{41-\sqrt{1321}}{15} for x_{2}.
x ^ 2 -\frac{82}{15}x +\frac{8}{5} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 15
r + s = \frac{82}{15} rs = \frac{8}{5}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{41}{15} - u s = \frac{41}{15} + u
Two numbers r and s sum up to \frac{82}{15} exactly when the average of the two numbers is \frac{1}{2}*\frac{82}{15} = \frac{41}{15}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{41}{15} - u) (\frac{41}{15} + u) = \frac{8}{5}
To solve for unknown quantity u, substitute these in the product equation rs = \frac{8}{5}
\frac{1681}{225} - u^2 = \frac{8}{5}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = \frac{8}{5}-\frac{1681}{225} = -\frac{1321}{225}
Simplify the expression by subtracting \frac{1681}{225} on both sides
u^2 = \frac{1321}{225} u = \pm\sqrt{\frac{1321}{225}} = \pm \frac{\sqrt{1321}}{15}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{41}{15} - \frac{\sqrt{1321}}{15} = 0.310 s = \frac{41}{15} + \frac{\sqrt{1321}}{15} = 5.156
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.