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15x^{2}-6+13x=0
Add 13x to both sides.
15x^{2}+13x-6=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=13 ab=15\left(-6\right)=-90
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as 15x^{2}+ax+bx-6. To find a and b, set up a system to be solved.
-1,90 -2,45 -3,30 -5,18 -6,15 -9,10
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -90.
-1+90=89 -2+45=43 -3+30=27 -5+18=13 -6+15=9 -9+10=1
Calculate the sum for each pair.
a=-5 b=18
The solution is the pair that gives sum 13.
\left(15x^{2}-5x\right)+\left(18x-6\right)
Rewrite 15x^{2}+13x-6 as \left(15x^{2}-5x\right)+\left(18x-6\right).
5x\left(3x-1\right)+6\left(3x-1\right)
Factor out 5x in the first and 6 in the second group.
\left(3x-1\right)\left(5x+6\right)
Factor out common term 3x-1 by using distributive property.
x=\frac{1}{3} x=-\frac{6}{5}
To find equation solutions, solve 3x-1=0 and 5x+6=0.
15x^{2}-6+13x=0
Add 13x to both sides.
15x^{2}+13x-6=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-13±\sqrt{13^{2}-4\times 15\left(-6\right)}}{2\times 15}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 15 for a, 13 for b, and -6 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-13±\sqrt{169-4\times 15\left(-6\right)}}{2\times 15}
Square 13.
x=\frac{-13±\sqrt{169-60\left(-6\right)}}{2\times 15}
Multiply -4 times 15.
x=\frac{-13±\sqrt{169+360}}{2\times 15}
Multiply -60 times -6.
x=\frac{-13±\sqrt{529}}{2\times 15}
Add 169 to 360.
x=\frac{-13±23}{2\times 15}
Take the square root of 529.
x=\frac{-13±23}{30}
Multiply 2 times 15.
x=\frac{10}{30}
Now solve the equation x=\frac{-13±23}{30} when ± is plus. Add -13 to 23.
x=\frac{1}{3}
Reduce the fraction \frac{10}{30} to lowest terms by extracting and canceling out 10.
x=-\frac{36}{30}
Now solve the equation x=\frac{-13±23}{30} when ± is minus. Subtract 23 from -13.
x=-\frac{6}{5}
Reduce the fraction \frac{-36}{30} to lowest terms by extracting and canceling out 6.
x=\frac{1}{3} x=-\frac{6}{5}
The equation is now solved.
15x^{2}-6+13x=0
Add 13x to both sides.
15x^{2}+13x=6
Add 6 to both sides. Anything plus zero gives itself.
\frac{15x^{2}+13x}{15}=\frac{6}{15}
Divide both sides by 15.
x^{2}+\frac{13}{15}x=\frac{6}{15}
Dividing by 15 undoes the multiplication by 15.
x^{2}+\frac{13}{15}x=\frac{2}{5}
Reduce the fraction \frac{6}{15} to lowest terms by extracting and canceling out 3.
x^{2}+\frac{13}{15}x+\left(\frac{13}{30}\right)^{2}=\frac{2}{5}+\left(\frac{13}{30}\right)^{2}
Divide \frac{13}{15}, the coefficient of the x term, by 2 to get \frac{13}{30}. Then add the square of \frac{13}{30} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+\frac{13}{15}x+\frac{169}{900}=\frac{2}{5}+\frac{169}{900}
Square \frac{13}{30} by squaring both the numerator and the denominator of the fraction.
x^{2}+\frac{13}{15}x+\frac{169}{900}=\frac{529}{900}
Add \frac{2}{5} to \frac{169}{900} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x+\frac{13}{30}\right)^{2}=\frac{529}{900}
Factor x^{2}+\frac{13}{15}x+\frac{169}{900}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{13}{30}\right)^{2}}=\sqrt{\frac{529}{900}}
Take the square root of both sides of the equation.
x+\frac{13}{30}=\frac{23}{30} x+\frac{13}{30}=-\frac{23}{30}
Simplify.
x=\frac{1}{3} x=-\frac{6}{5}
Subtract \frac{13}{30} from both sides of the equation.