Solve 15x+5+22x+4

$$15 x + 5 + 22 x + 4$$

Evaluate

$$37x+9$$

Solution Steps

Combine 15x and 22x to get 37x.

$$37x+5+4$$

Add 5 and 4 to get 9.

$$37x+9$$

Differentiate w.r.t. x

$$37$$

Steps Using Derivative Rule for Sum

Combine 15x and 22x to get 37x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(37x+5+4)$$

Add 5 and 4 to get 9.

$$\frac{\mathrm{d}}{\mathrm{d}x}(37x+9)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$37x^{1-1}$$

Subtract 1 from 1.

$$37x^{0}$$

For any term t except 0, t^{0}=1.

$$37\times 1$$

For any term t, t\times 1=t and 1t=t.

$$37$$