Solve 15x+18geq-17x-20

$$15 x + 18 \geq - 17 x - 20$$

Solve for x

$$x\geq -\frac{19}{16}$$

Solution Steps

Add 17x to both sides.

$$15x+18+17x\geq -20$$

Combine 15x and 17x to get 32x.

$$32x+18\geq -20$$

Subtract 18 from both sides.

$$32x\geq -20-18$$

Subtract 18 from -20 to get -38.

$$32x\geq -38$$

Divide both sides by 32. Since 32 is positive, the inequality direction remains the same.

$$x\geq \frac{-38}{32}$$

Reduce the fraction \frac{-38}{32} to lowest terms by extracting and canceling out 2.

$$x\geq -\frac{19}{16}$$