Solve for x
x\leq \frac{1}{2}
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15-7x+x\geq 12
Add x to both sides.
15-6x\geq 12
Combine -7x and x to get -6x.
-6x\geq 12-15
Subtract 15 from both sides.
-6x\geq -3
Subtract 15 from 12 to get -3.
x\leq \frac{-3}{-6}
Divide both sides by -6. Since -6 is negative, the inequality direction is changed.
x\leq \frac{1}{2}
Reduce the fraction \frac{-3}{-6} to lowest terms by extracting and canceling out -3.
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Limits
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