Solve 15-28i=3ell+(4m)

$$15 - 28 i = 3 \ell + ( 4 m )$$

Solve for m

$$m=-\frac{3ℓ}{4}+\left(\frac{15}{4}-7i\right)$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$3ℓ+4m=15-28i$$

Subtract 3ℓ from both sides.

$$4m=15-28i-3ℓ$$

Divide both sides by 4.

$$\frac{4m}{4}=\frac{15-28i-3ℓ}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$m=\frac{15-28i-3ℓ}{4}$$

Divide 15-28i-3ℓ by 4.

$$m=-\frac{3ℓ}{4}+\left(\frac{15}{4}-7i\right)$$

Solve for ℓ

$$ℓ=-\frac{4m}{3}+\left(5-\frac{28}{3}i\right)$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$3ℓ+4m=15-28i$$

Subtract 4m from both sides.

$$3ℓ=15-28i-4m$$

Divide both sides by 3.

$$\frac{3ℓ}{3}=\frac{15-28i-4m}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$ℓ=\frac{15-28i-4m}{3}$$

Divide 15-28i-4m by 3.

$$ℓ=-\frac{4m}{3}+\left(5-\frac{28}{3}i\right)$$