Solve 15(1/3+4/9*3)

$$15 ( \frac { 1 } { 3 } + \frac { 4 } { 9 } \cdot 3 )$$

Evaluate

$$25$$

Solution Steps

Express \frac{4}{9}\times 3 as a single fraction.

$$15\left(\frac{1}{3}+\frac{4\times 3}{9}\right)$$

Multiply 4 and 3 to get 12.

$$15\left(\frac{1}{3}+\frac{12}{9}\right)$$

Reduce the fraction \frac{12}{9} to lowest terms by extracting and canceling out 3.

$$15\left(\frac{1}{3}+\frac{4}{3}\right)$$

Since \frac{1}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$15\times \frac{1+4}{3}$$

Add 1 and 4 to get 5.

$$15\times \frac{5}{3}$$

Express 15\times \frac{5}{3} as a single fraction.

$$\frac{15\times 5}{3}$$

Multiply 15 and 5 to get 75.

$$\frac{75}{3}$$

Divide 75 by 3 to get 25.

$$25$$

Factor

$$5^{2}$$