Solve 151/1[5/7*(2/3-1/5)]

$$15 \frac { 1 } { 1 } [ \frac { 5 } { 7 } \times ( \frac { 2 } { 3 } - \frac { 1 } { 5 } ) ]$$

Evaluate

$$\frac{16}{3}\approx 5.333333333$$

Solution Steps

Multiply 15 and 1 to get 15.

$$\frac{15+1}{1}\times \frac{5}{7}\left(\frac{2}{3}-\frac{1}{5}\right)$$

Add 15 and 1 to get 16.

$$\frac{16}{1}\times \frac{5}{7}\left(\frac{2}{3}-\frac{1}{5}\right)$$

Anything divided by one gives itself.

$$16\times \frac{5}{7}\left(\frac{2}{3}-\frac{1}{5}\right)$$

Express 16\times \frac{5}{7} as a single fraction.

$$\frac{16\times 5}{7}\left(\frac{2}{3}-\frac{1}{5}\right)$$

Multiply 16 and 5 to get 80.

$$\frac{80}{7}\left(\frac{2}{3}-\frac{1}{5}\right)$$

Least common multiple of 3 and 5 is 15. Convert \frac{2}{3} and \frac{1}{5} to fractions with denominator 15.

$$\frac{80}{7}\left(\frac{10}{15}-\frac{3}{15}\right)$$

Since \frac{10}{15} and \frac{3}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{80}{7}\times \frac{10-3}{15}$$

Subtract 3 from 10 to get 7.

$$\frac{80}{7}\times \frac{7}{15}$$

Multiply \frac{80}{7} times \frac{7}{15} by multiplying numerator times numerator and denominator times denominator.

$$\frac{80\times 7}{7\times 15}$$

Cancel out 7 in both numerator and denominator.

$$\frac{80}{15}$$

Reduce the fraction \frac{80}{15} to lowest terms by extracting and canceling out 5.

$$\frac{16}{3}$$

Factor

$$\frac{2 ^ {4}}{3} = 5\frac{1}{3} = 5.333333333333333$$