Solve 140*1^4-9*1^2-1

$$140 \times { 1 }^{ 4 } -9 \times { 1 }^{ 2 } -1$$

Evaluate

$$130$$

Solution Steps

Calculate 1 to the power of 4 and get 1.

$$140\times 1-9\times 1^{2}-1$$

Multiply 140 and 1 to get 140.

$$140-9\times 1^{2}-1$$

Calculate 1 to the power of 2 and get 1.

$$140-9\times 1-1$$

Multiply 9 and 1 to get 9.

$$140-9-1$$

Subtract 9 from 140 to get 131.

$$131-1$$

Subtract 1 from 131 to get 130.

$$130$$

Factor

$$2\times 5\times 13$$