Factor
\left(7x+5\right)\left(2x^{2}-1\right)
Evaluate
\left(7x+5\right)\left(2x^{2}-1\right)
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2x^{2}\left(7x+5\right)-\left(7x+5\right)
Do the grouping 14x^{3}+10x^{2}-7x-5=\left(14x^{3}+10x^{2}\right)+\left(-7x-5\right), and factor out 2x^{2} in the first and -1 in the second group.
\left(7x+5\right)\left(2x^{2}-1\right)
Factor out common term 7x+5 by using distributive property. Polynomial 2x^{2}-1 is not factored since it does not have any rational roots.
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