Solve 14-ax=bx-c

$$14 - a x = b x - c$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=\frac{14+c-bx}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&c=-14\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 14 from both sides.

$$-ax=bx-c-14$$

The equation is in standard form.

$$\left(-x\right)a=bx-c-14$$

Divide both sides by -x.

$$\frac{\left(-x\right)a}{-x}=\frac{bx-c-14}{-x}$$

Dividing by -x undoes the multiplication by -x.

$$a=\frac{bx-c-14}{-x}$$

Divide bx-c-14 by -x.

$$a=-\frac{bx-c-14}{x}$$

Solve for b (complex solution)

$$\left\{\begin{matrix}b=-\frac{ax-c-14}{x}\text{, }&x\neq 0\\b\in \mathrm{C}\text{, }&c=-14\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$bx-c=14-ax$$

Add c to both sides.

$$bx=14-ax+c$$

The equation is in standard form.

$$xb=14+c-ax$$

Divide both sides by x.

$$\frac{xb}{x}=\frac{14+c-ax}{x}$$

Dividing by x undoes the multiplication by x.

$$b=\frac{14+c-ax}{x}$$

Solve for a

$$\left\{\begin{matrix}a=\frac{14+c-bx}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&c=-14\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 14 from both sides.

$$-ax=bx-c-14$$

The equation is in standard form.

$$\left(-x\right)a=bx-c-14$$

Divide both sides by -x.

$$\frac{\left(-x\right)a}{-x}=\frac{bx-c-14}{-x}$$

Dividing by -x undoes the multiplication by -x.

$$a=\frac{bx-c-14}{-x}$$

Divide bx-c-14 by -x.

$$a=-\frac{bx-c-14}{x}$$

Solve for b

$$\left\{\begin{matrix}b=-\frac{ax-c-14}{x}\text{, }&x\neq 0\\b\in \mathrm{R}\text{, }&c=-14\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$bx-c=14-ax$$

Add c to both sides.

$$bx=14-ax+c$$

The equation is in standard form.

$$xb=14+c-ax$$

Divide both sides by x.

$$\frac{xb}{x}=\frac{14+c-ax}{x}$$

Dividing by x undoes the multiplication by x.

$$b=\frac{14+c-ax}{x}$$