Solve 14-3/+81-3/+162-1/4+43-1/2

$$14 - 3 / + 8 1 - 3 / + 16 2 - 1 / 4 + 43 - 1 / 2$$

Evaluate

$$\frac{111}{2}=55.5$$

Solution Steps

Multiply \frac{3}{8} and 1 to get \frac{3}{8}.

$$14-\frac{3}{8}-\frac{3}{16}\times 2-\frac{1}{4}+43-\frac{1}{2}$$

Convert 14 to fraction \frac{112}{8}.

$$\frac{112}{8}-\frac{3}{8}-\frac{3}{16}\times 2-\frac{1}{4}+43-\frac{1}{2}$$

Since \frac{112}{8} and \frac{3}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{112-3}{8}-\frac{3}{16}\times 2-\frac{1}{4}+43-\frac{1}{2}$$

Subtract 3 from 112 to get 109.

$$\frac{109}{8}-\frac{3}{16}\times 2-\frac{1}{4}+43-\frac{1}{2}$$

Express \frac{3}{16}\times 2 as a single fraction.

$$\frac{109}{8}-\frac{3\times 2}{16}-\frac{1}{4}+43-\frac{1}{2}$$

Multiply 3 and 2 to get 6.

$$\frac{109}{8}-\frac{6}{16}-\frac{1}{4}+43-\frac{1}{2}$$

Reduce the fraction \frac{6}{16} to lowest terms by extracting and canceling out 2.

$$\frac{109}{8}-\frac{3}{8}-\frac{1}{4}+43-\frac{1}{2}$$

Since \frac{109}{8} and \frac{3}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{109-3}{8}-\frac{1}{4}+43-\frac{1}{2}$$

Subtract 3 from 109 to get 106.

$$\frac{106}{8}-\frac{1}{4}+43-\frac{1}{2}$$

Reduce the fraction \frac{106}{8} to lowest terms by extracting and canceling out 2.

$$\frac{53}{4}-\frac{1}{4}+43-\frac{1}{2}$$

Since \frac{53}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{53-1}{4}+43-\frac{1}{2}$$

Subtract 1 from 53 to get 52.

$$\frac{52}{4}+43-\frac{1}{2}$$

Divide 52 by 4 to get 13.

$$13+43-\frac{1}{2}$$

Add 13 and 43 to get 56.

$$56-\frac{1}{2}$$

Convert 56 to fraction \frac{112}{2}.

$$\frac{112}{2}-\frac{1}{2}$$

Since \frac{112}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{112-1}{2}$$

Subtract 1 from 112 to get 111.

$$\frac{111}{2}$$

Factor

$$\frac{3 \cdot 37}{2} = 55\frac{1}{2} = 55.5$$