Solve 14x^2+4x-9-3/7+36/7x

$$14 { x }^{ 2 } +4x-9- \frac{ 3 }{ 7 } + \frac{ 36 }{ 7x }$$

Evaluate

$$14x^{2}+4x-\frac{66}{7}+\frac{36}{7x}$$

Short Solution Steps

Subtract \frac{3}{7} from -9 to get -\frac{66}{7}.

$$14x^{2}+4x-\frac{66}{7}+\frac{36}{7x}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 7 and 7x is 7x. Multiply \frac{66}{7} times \frac{x}{x}.

$$14x^{2}+4x-\frac{66x}{7x}+\frac{36}{7x}$$

Since -\frac{66x}{7x} and \frac{36}{7x} have the same denominator, add them by adding their numerators.

$$14x^{2}+4x+\frac{-66x+36}{7x}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 14x^{2}+4x times \frac{7x}{7x}.

$$\frac{\left(14x^{2}+4x\right)\times 7x}{7x}+\frac{-66x+36}{7x}$$

Since \frac{\left(14x^{2}+4x\right)\times 7x}{7x} and \frac{-66x+36}{7x} have the same denominator, add them by adding their numerators.

$$\frac{\left(14x^{2}+4x\right)\times 7x-66x+36}{7x}$$

Do the multiplications in \left(14x^{2}+4x\right)\times 7x-66x+36.

$$\frac{98x^{3}+28x^{2}-66x+36}{7x}$$

Factor

$$\frac{2\left(49x^{3}+14x^{2}-33x+18\right)}{7x}$$