Solve 14{left(1/7right)}^2-231/7

$$14 { \left( \frac{ 1 }{ 7 } \right) }^{ 2 } -23 \frac{ 1 }{ 7 }$$

Evaluate

$$-\frac{160}{7}\approx -22.857142857$$

Solution Steps

Calculate \frac{1}{7} to the power of 2 and get \frac{1}{49}.

$$14\times \frac{1}{49}-\frac{23\times 7+1}{7}$$

Multiply 14 and \frac{1}{49} to get \frac{14}{49}.

$$\frac{14}{49}-\frac{23\times 7+1}{7}$$

Reduce the fraction \frac{14}{49} to lowest terms by extracting and canceling out 7.

$$\frac{2}{7}-\frac{23\times 7+1}{7}$$

Multiply 23 and 7 to get 161.

$$\frac{2}{7}-\frac{161+1}{7}$$

Add 161 and 1 to get 162.

$$\frac{2}{7}-\frac{162}{7}$$

Since \frac{2}{7} and \frac{162}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-162}{7}$$

Subtract 162 from 2 to get -160.

$$-\frac{160}{7}$$

Factor

$$-\frac{160}{7} = -22\frac{6}{7} = -22.857142857142858$$