Solve for x
x=6
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\frac{14}{42}=\frac{x}{x+12}
Divide both sides by 42.
\frac{1}{3}=\frac{x}{x+12}
Reduce the fraction \frac{14}{42} to lowest terms by extracting and canceling out 14.
x+12=3x
Variable x cannot be equal to -12 since division by zero is not defined. Multiply both sides of the equation by 3\left(x+12\right), the least common multiple of 3,x+12.
x+12-3x=0
Subtract 3x from both sides.
-2x+12=0
Combine x and -3x to get -2x.
-2x=-12
Subtract 12 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-12}{-2}
Divide both sides by -2.
x=6
Divide -12 by -2 to get 6.
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