Solve 14+(12-3-2)+(20+1):3-[12*(3+1)-5*8]

$$14 + ( 12 - 3 - 2 ) + ( 20 + 1 ) : 3 - [ 12 \cdot ( 3 + 1 ) - 5 \cdot 8 ]$$

Evaluate

$$20$$

Solution Steps

Add 14 and 12 to get 26.

$$26-3-2+\frac{20+1}{3}-\left(12\left(3+1\right)-5\times 8\right)$$

Subtract 3 from 26 to get 23.

$$23-2+\frac{20+1}{3}-\left(12\left(3+1\right)-5\times 8\right)$$

Subtract 2 from 23 to get 21.

$$21+\frac{20+1}{3}-\left(12\left(3+1\right)-5\times 8\right)$$

Add 20 and 1 to get 21.

$$21+\frac{21}{3}-\left(12\left(3+1\right)-5\times 8\right)$$

Divide 21 by 3 to get 7.

$$21+7-\left(12\left(3+1\right)-5\times 8\right)$$

Add 21 and 7 to get 28.

$$28-\left(12\left(3+1\right)-5\times 8\right)$$

Add 3 and 1 to get 4.

$$28-\left(12\times 4-5\times 8\right)$$

Multiply 12 and 4 to get 48.

$$28-\left(48-5\times 8\right)$$

Multiply 5 and 8 to get 40.

$$28-\left(48-40\right)$$

Subtract 40 from 48 to get 8.

$$28-8$$

Subtract 8 from 28 to get 20.

$$20$$

Factor

$$2^{2}\times 5$$