Solve 130*5%+9%*(x-130)

$$130 \times 5 \% +9 \% \times (x-130)$$

Evaluate

$$\frac{9x}{100}-\frac{26}{5}$$

Solution Steps

Reduce the fraction \frac{5}{100} to lowest terms by extracting and canceling out 5.

$$130\times \frac{1}{20}+\frac{9}{100}\left(x-130\right)$$

Multiply 130 and \frac{1}{20} to get \frac{130}{20}.

$$\frac{130}{20}+\frac{9}{100}\left(x-130\right)$$

Reduce the fraction \frac{130}{20} to lowest terms by extracting and canceling out 10.

$$\frac{13}{2}+\frac{9}{100}\left(x-130\right)$$

Use the distributive property to multiply \frac{9}{100} by x-130.

$$\frac{13}{2}+\frac{9}{100}x+\frac{9}{100}\left(-130\right)$$

Express \frac{9}{100}\left(-130\right) as a single fraction.

$$\frac{13}{2}+\frac{9}{100}x+\frac{9\left(-130\right)}{100}$$

Multiply 9 and -130 to get -1170.

$$\frac{13}{2}+\frac{9}{100}x+\frac{-1170}{100}$$

Reduce the fraction \frac{-1170}{100} to lowest terms by extracting and canceling out 10.

$$\frac{13}{2}+\frac{9}{100}x-\frac{117}{10}$$

Least common multiple of 2 and 10 is 10. Convert \frac{13}{2} and \frac{117}{10} to fractions with denominator 10.

$$\frac{65}{10}+\frac{9}{100}x-\frac{117}{10}$$

Since \frac{65}{10} and \frac{117}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{65-117}{10}+\frac{9}{100}x$$

Subtract 117 from 65 to get -52.

$$\frac{-52}{10}+\frac{9}{100}x$$

Reduce the fraction \frac{-52}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{26}{5}+\frac{9}{100}x$$

Expand

$$\frac{9x}{100}-\frac{26}{5}$$

Solution Steps

Reduce the fraction \frac{5}{100} to lowest terms by extracting and canceling out 5.

$$130\times \frac{1}{20}+\frac{9}{100}\left(x-130\right)$$

Multiply 130 and \frac{1}{20} to get \frac{130}{20}.

$$\frac{130}{20}+\frac{9}{100}\left(x-130\right)$$

Reduce the fraction \frac{130}{20} to lowest terms by extracting and canceling out 10.

$$\frac{13}{2}+\frac{9}{100}\left(x-130\right)$$

Use the distributive property to multiply \frac{9}{100} by x-130.

$$\frac{13}{2}+\frac{9}{100}x+\frac{9}{100}\left(-130\right)$$

Express \frac{9}{100}\left(-130\right) as a single fraction.

$$\frac{13}{2}+\frac{9}{100}x+\frac{9\left(-130\right)}{100}$$

Multiply 9 and -130 to get -1170.

$$\frac{13}{2}+\frac{9}{100}x+\frac{-1170}{100}$$

Reduce the fraction \frac{-1170}{100} to lowest terms by extracting and canceling out 10.

$$\frac{13}{2}+\frac{9}{100}x-\frac{117}{10}$$

Least common multiple of 2 and 10 is 10. Convert \frac{13}{2} and \frac{117}{10} to fractions with denominator 10.

$$\frac{65}{10}+\frac{9}{100}x-\frac{117}{10}$$

Since \frac{65}{10} and \frac{117}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{65-117}{10}+\frac{9}{100}x$$

Subtract 117 from 65 to get -52.

$$\frac{-52}{10}+\frac{9}{100}x$$

Reduce the fraction \frac{-52}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{26}{5}+\frac{9}{100}x$$