Solve 13^0+27*(1/60)^0+36*(1/360)^0

$$13 ^ { 0 } + 27 \cdot ( \frac { 1 } { 60 } ) ^ { 0 } + 36 \cdot ( \frac { 1 } { 360 } ) ^ { 0 }$$

Evaluate

$$64$$

Solution Steps

Calculate 13 to the power of 0 and get 1.

$$1+27\times \left(\frac{1}{60}\right)^{0}+36\times \left(\frac{1}{360}\right)^{0}$$

Calculate \frac{1}{60} to the power of 0 and get 1.

$$1+27\times 1+36\times \left(\frac{1}{360}\right)^{0}$$

Multiply 27 and 1 to get 27.

$$1+27+36\times \left(\frac{1}{360}\right)^{0}$$

Add 1 and 27 to get 28.

$$28+36\times \left(\frac{1}{360}\right)^{0}$$

Calculate \frac{1}{360} to the power of 0 and get 1.

$$28+36\times 1$$

Multiply 36 and 1 to get 36.

$$28+36$$

Add 28 and 36 to get 64.

$$64$$

Factor

$$2^{6}$$