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2\left(64x^{3}-1\right)
Factor out 2.
\left(4x-1\right)\left(16x^{2}+4x+1\right)
Consider 64x^{3}-1. Rewrite 64x^{3}-1 as \left(4x\right)^{3}-1^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
2\left(4x-1\right)\left(16x^{2}+4x+1\right)
Rewrite the complete factored expression. Polynomial 16x^{2}+4x+1 is not factored since it does not have any rational roots.