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Differentiate w.r.t. x_1281
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\begin{array}{c}\phantom{\times999}12782\\\underline{\times\phantom{9999}1281}\\\end{array}
First line up the numbers vertically and match the places from the right like this.
\begin{array}{c}\phantom{\times999}12782\\\underline{\times\phantom{9999}1281}\\\phantom{\times999}12782\\\end{array}
Now multiply the first number with the 1^{st} digit in 2^{nd} number to get intermediate results. That is Multiply 12782 with 1. Write the result 12782 at the end leaving 0 spaces to the right like this.
\begin{array}{c}\phantom{\times999}12782\\\underline{\times\phantom{9999}1281}\\\phantom{\times999}12782\\\phantom{\times9}102256\phantom{9}\\\end{array}
Now multiply the first number with the 2^{nd} digit in 2^{nd} number to get intermediate results. That is Multiply 12782 with 8. Write the result 102256 at the end leaving 1 spaces to the right like this.
\begin{array}{c}\phantom{\times999}12782\\\underline{\times\phantom{9999}1281}\\\phantom{\times999}12782\\\phantom{\times9}102256\phantom{9}\\\phantom{\times9}25564\phantom{99}\\\end{array}
Now multiply the first number with the 3^{rd} digit in 2^{nd} number to get intermediate results. That is Multiply 12782 with 2. Write the result 25564 at the end leaving 2 spaces to the right like this.
\begin{array}{c}\phantom{\times999}12782\\\underline{\times\phantom{9999}1281}\\\phantom{\times999}12782\\\phantom{\times9}102256\phantom{9}\\\phantom{\times9}25564\phantom{99}\\\underline{\phantom{\times}12782\phantom{999}}\\\end{array}
Now multiply the first number with the 4^{th} digit in 2^{nd} number to get intermediate results. That is Multiply 12782 with 1. Write the result 12782 at the end leaving 3 spaces to the right like this.
\begin{array}{c}\phantom{\times999}12782\\\underline{\times\phantom{9999}1281}\\\phantom{\times999}12782\\\phantom{\times9}102256\phantom{9}\\\phantom{\times9}25564\phantom{99}\\\underline{\phantom{\times}12782\phantom{999}}\\\phantom{\times}16373742\end{array}
Now add the intermediate results to get final answer.
12782x_{1281}^{1-1}
The derivative of ax^{n} is nax^{n-1}.
12782x_{1281}^{0}
Subtract 1 from 1.
12782\times 1
For any term t except 0, t^{0}=1.
12782
For any term t, t\times 1=t and 1t=t.