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120x^{2}\times 1.5=240
Multiply x and x to get x^{2}.
180x^{2}=240
Multiply 120 and 1.5 to get 180.
x^{2}=\frac{240}{180}
Divide both sides by 180.
x^{2}=\frac{4}{3}
Reduce the fraction \frac{240}{180} to lowest terms by extracting and canceling out 60.
x=\frac{2\sqrt{3}}{3} x=-\frac{2\sqrt{3}}{3}
Take the square root of both sides of the equation.
120x^{2}\times 1.5=240
Multiply x and x to get x^{2}.
180x^{2}=240
Multiply 120 and 1.5 to get 180.
180x^{2}-240=0
Subtract 240 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 180\left(-240\right)}}{2\times 180}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 180 for a, 0 for b, and -240 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 180\left(-240\right)}}{2\times 180}
Square 0.
x=\frac{0±\sqrt{-720\left(-240\right)}}{2\times 180}
Multiply -4 times 180.
x=\frac{0±\sqrt{172800}}{2\times 180}
Multiply -720 times -240.
x=\frac{0±240\sqrt{3}}{2\times 180}
Take the square root of 172800.
x=\frac{0±240\sqrt{3}}{360}
Multiply 2 times 180.
x=\frac{2\sqrt{3}}{3}
Now solve the equation x=\frac{0±240\sqrt{3}}{360} when ± is plus.
x=-\frac{2\sqrt{3}}{3}
Now solve the equation x=\frac{0±240\sqrt{3}}{360} when ± is minus.
x=\frac{2\sqrt{3}}{3} x=-\frac{2\sqrt{3}}{3}
The equation is now solved.