Solve for x
x=-\frac{33y}{40}+10
Solve for y
y=\frac{400-40x}{33}
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120x=1200-99y
Subtract 99y from both sides.
\frac{120x}{120}=\frac{1200-99y}{120}
Divide both sides by 120.
x=\frac{1200-99y}{120}
Dividing by 120 undoes the multiplication by 120.
x=-\frac{33y}{40}+10
Divide 1200-99y by 120.
99y=1200-120x
Subtract 120x from both sides.
\frac{99y}{99}=\frac{1200-120x}{99}
Divide both sides by 99.
y=\frac{1200-120x}{99}
Dividing by 99 undoes the multiplication by 99.
y=\frac{400-40x}{33}
Divide 1200-120x by 99.
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