Solve 120^circ+x=180^circad

$$120 ^ { \circ } + x = 180 ^ { \circ } ad$$

Solve for a

$$\left\{\begin{matrix}a=\frac{x+120}{180d}\text{, }&d\neq 0\\a\in \mathrm{R}\text{, }&x=-120\text{ and }d=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$180ad=120+x$$

The equation is in standard form.

$$180da=x+120$$

Divide both sides by 180d.

$$\frac{180da}{180d}=\frac{x+120}{180d}$$

Dividing by 180d undoes the multiplication by 180d.

$$a=\frac{x+120}{180d}$$

Solve for d

$$\left\{\begin{matrix}d=\frac{x+120}{180a}\text{, }&a\neq 0\\d\in \mathrm{R}\text{, }&x=-120\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$180ad=120+x$$

The equation is in standard form.

$$180ad=x+120$$

Divide both sides by 180a.

$$\frac{180ad}{180a}=\frac{x+120}{180a}$$

Dividing by 180a undoes the multiplication by 180a.

$$d=\frac{x+120}{180a}$$