Solve 12+3(-6+2(5-4(3-2)+5(7-8))-5)

$$12+3(-6+2(5-4(3-2)+5(7-8))-5)$$

Evaluate

$$-45$$

Solution Steps

Subtract 2 from 3 to get 1.

$$12+3\left(-6+2\left(5-4\times 1+5\left(7-8\right)\right)-5\right)$$

Multiply 4 and 1 to get 4.

$$12+3\left(-6+2\left(5-4+5\left(7-8\right)\right)-5\right)$$

Subtract 4 from 5 to get 1.

$$12+3\left(-6+2\left(1+5\left(7-8\right)\right)-5\right)$$

Subtract 8 from 7 to get -1.

$$12+3\left(-6+2\left(1+5\left(-1\right)\right)-5\right)$$

Multiply 5 and -1 to get -5.

$$12+3\left(-6+2\left(1-5\right)-5\right)$$

Subtract 5 from 1 to get -4.

$$12+3\left(-6+2\left(-4\right)-5\right)$$

Multiply 2 and -4 to get -8.

$$12+3\left(-6-8-5\right)$$

Subtract 8 from -6 to get -14.

$$12+3\left(-14-5\right)$$

Subtract 5 from -14 to get -19.

$$12+3\left(-19\right)$$

Multiply 3 and -19 to get -57.

$$12-57$$

Subtract 57 from 12 to get -45.

$$-45$$

Factor

$$-45$$