Solve 12y=10y^2

$$12 y = 10 y ^ { 2 }$$

Solve for y

$$y = \frac{6}{5} = 1\frac{1}{5} = 1.2$$

$$y=0$$

Steps Using Factoring

Subtract 10y^{2} from both sides.

$$12y-10y^{2}=0$$

Factor out y.

$$y\left(12-10y\right)=0$$

To find equation solutions, solve y=0 and 12-10y=0.

$$y=0 y=\frac{6}{5}$$

Steps Using the Quadratic Formula

Subtract 10y^{2} from both sides.

$$12y-10y^{2}=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$-10y^{2}+12y=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -10 for a, 12 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{-12±\sqrt{12^{2}}}{2\left(-10\right)}$$

Take the square root of 12^{2}.

$$y=\frac{-12±12}{2\left(-10\right)}$$

Multiply 2 times -10.

$$y=\frac{-12±12}{-20}$$

Now solve the equation y=\frac{-12±12}{-20} when ± is plus. Add -12 to 12.

$$y=\frac{0}{-20}$$

Divide 0 by -20.

$$y=0$$

Now solve the equation y=\frac{-12±12}{-20} when ± is minus. Subtract 12 from -12.

$$y=-\frac{24}{-20}$$

Reduce the fraction \frac{-24}{-20} to lowest terms by extracting and canceling out 4.

$$y=\frac{6}{5}$$

The equation is now solved.

$$y=0 y=\frac{6}{5}$$

Steps for Completing the Square

Subtract 10y^{2} from both sides.

$$12y-10y^{2}=0$$

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$-10y^{2}+12y=0$$

Divide both sides by -10.

$$\frac{-10y^{2}+12y}{-10}=\frac{0}{-10}$$

Dividing by -10 undoes the multiplication by -10.

$$y^{2}+\frac{12}{-10}y=\frac{0}{-10}$$

Reduce the fraction \frac{12}{-10} to lowest terms by extracting and canceling out 2.

$$y^{2}-\frac{6}{5}y=\frac{0}{-10}$$

Divide 0 by -10.

$$y^{2}-\frac{6}{5}y=0$$

Divide -\frac{6}{5}, the coefficient of the x term, by 2 to get -\frac{3}{5}. Then add the square of -\frac{3}{5} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$y^{2}-\frac{6}{5}y+\left(-\frac{3}{5}\right)^{2}=\left(-\frac{3}{5}\right)^{2}$$

Square -\frac{3}{5} by squaring both the numerator and the denominator of the fraction.

$$y^{2}-\frac{6}{5}y+\frac{9}{25}=\frac{9}{25}$$

Factor y^{2}-\frac{6}{5}y+\frac{9}{25}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(y-\frac{3}{5}\right)^{2}=\frac{9}{25}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(y-\frac{3}{5}\right)^{2}}=\sqrt{\frac{9}{25}}$$

Simplify.

$$y-\frac{3}{5}=\frac{3}{5} y-\frac{3}{5}=-\frac{3}{5}$$

Add \frac{3}{5} to both sides of the equation.

$$y=\frac{6}{5} y=0$$