Solve for x
x=\frac{2y}{3}+1
Solve for y
y=\frac{3\left(x-1\right)}{2}
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12x=12+8y
Add 8y to both sides.
12x=8y+12
The equation is in standard form.
\frac{12x}{12}=\frac{8y+12}{12}
Divide both sides by 12.
x=\frac{8y+12}{12}
Dividing by 12 undoes the multiplication by 12.
x=\frac{2y}{3}+1
Divide 12+8y by 12.
-8y=12-12x
Subtract 12x from both sides.
\frac{-8y}{-8}=\frac{12-12x}{-8}
Divide both sides by -8.
y=\frac{12-12x}{-8}
Dividing by -8 undoes the multiplication by -8.
y=\frac{3x-3}{2}
Divide 12-12x by -8.
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