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x\left(12x^{2}+11x+2\right)
Factor out x.
a+b=11 ab=12\times 2=24
Consider 12x^{2}+11x+2. Factor the expression by grouping. First, the expression needs to be rewritten as 12x^{2}+ax+bx+2. To find a and b, set up a system to be solved.
1,24 2,12 3,8 4,6
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 24.
1+24=25 2+12=14 3+8=11 4+6=10
Calculate the sum for each pair.
a=3 b=8
The solution is the pair that gives sum 11.
\left(12x^{2}+3x\right)+\left(8x+2\right)
Rewrite 12x^{2}+11x+2 as \left(12x^{2}+3x\right)+\left(8x+2\right).
3x\left(4x+1\right)+2\left(4x+1\right)
Factor out 3x in the first and 2 in the second group.
\left(4x+1\right)\left(3x+2\right)
Factor out common term 4x+1 by using distributive property.
x\left(4x+1\right)\left(3x+2\right)
Rewrite the complete factored expression.