Solve for x
x=-\frac{2y}{3}+\frac{7}{12}
Solve for y
y=-\frac{3x}{2}+\frac{7}{8}
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12x=7-8y
Subtract 8y from both sides.
\frac{12x}{12}=\frac{7-8y}{12}
Divide both sides by 12.
x=\frac{7-8y}{12}
Dividing by 12 undoes the multiplication by 12.
x=-\frac{2y}{3}+\frac{7}{12}
Divide 7-8y by 12.
8y=7-12x
Subtract 12x from both sides.
\frac{8y}{8}=\frac{7-12x}{8}
Divide both sides by 8.
y=\frac{7-12x}{8}
Dividing by 8 undoes the multiplication by 8.
y=-\frac{3x}{2}+\frac{7}{8}
Divide 7-12x by 8.
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