Solve 12a-26=5b-2c

$$12 a - 26 = 5 b - 2 c$$

Solve for a

$$a=\frac{5b}{12}-\frac{c}{6}+\frac{13}{6}$$

Steps for Solving Linear Equation

Add 26 to both sides.

$$12a=5b-2c+26$$

Divide both sides by 12.

$$\frac{12a}{12}=\frac{5b-2c+26}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$a=\frac{5b-2c+26}{12}$$

Divide 5b-2c+26 by 12.

$$a=\frac{5b}{12}-\frac{c}{6}+\frac{13}{6}$$

Solve for b

$$b=\frac{2\left(6a+c-13\right)}{5}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$5b-2c=12a-26$$

Add 2c to both sides.

$$5b=12a-26+2c$$

The equation is in standard form.

$$5b=12a+2c-26$$

Divide both sides by 5.

$$\frac{5b}{5}=\frac{12a+2c-26}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$b=\frac{12a+2c-26}{5}$$