Solve 12-3div6-3+12

$$12 - 3 \div 6 - 3 + 12$$

Evaluate

$$\frac{41}{2}=20.5$$

Solution Steps

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$12-\frac{1}{2}-3+12$$

Convert 12 to fraction \frac{24}{2}.

$$\frac{24}{2}-\frac{1}{2}-3+12$$

Since \frac{24}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{24-1}{2}-3+12$$

Subtract 1 from 24 to get 23.

$$\frac{23}{2}-3+12$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{23}{2}-\frac{6}{2}+12$$

Since \frac{23}{2} and \frac{6}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{23-6}{2}+12$$

Subtract 6 from 23 to get 17.

$$\frac{17}{2}+12$$

Convert 12 to fraction \frac{24}{2}.

$$\frac{17}{2}+\frac{24}{2}$$

Since \frac{17}{2} and \frac{24}{2} have the same denominator, add them by adding their numerators.

$$\frac{17+24}{2}$$

Add 17 and 24 to get 41.

$$\frac{41}{2}$$

Factor

$$\frac{41}{2} = 20\frac{1}{2} = 20.5$$