Solve 12div(1/3+1/4)

$$12 \div ( \frac { 1 } { 3 } + \frac { 1 } { 4 } )$$

Evaluate

$$\frac{144}{7}\approx 20.571428571$$

Solution Steps

Least common multiple of 3 and 4 is 12. Convert \frac{1}{3} and \frac{1}{4} to fractions with denominator 12.

$$\frac{12}{\frac{4}{12}+\frac{3}{12}}$$

Since \frac{4}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{12}{\frac{4+3}{12}}$$

Add 4 and 3 to get 7.

$$\frac{12}{\frac{7}{12}}$$

Divide 12 by \frac{7}{12} by multiplying 12 by the reciprocal of \frac{7}{12}.

$$12\times \frac{12}{7}$$

Express 12\times \frac{12}{7} as a single fraction.

$$\frac{12\times 12}{7}$$

Multiply 12 and 12 to get 144.

$$\frac{144}{7}$$

Factor

$$\frac{2 ^ {4} \cdot 3 ^ {2}}{7} = 20\frac{4}{7} = 20.571428571428573$$