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76-16t^{2}=12
Swap sides so that all variable terms are on the left hand side.
-16t^{2}=12-76
Subtract 76 from both sides.
-16t^{2}=-64
Subtract 76 from 12 to get -64.
t^{2}=\frac{-64}{-16}
Divide both sides by -16.
t^{2}=4
Divide -64 by -16 to get 4.
t=2 t=-2
Take the square root of both sides of the equation.
76-16t^{2}=12
Swap sides so that all variable terms are on the left hand side.
76-16t^{2}-12=0
Subtract 12 from both sides.
64-16t^{2}=0
Subtract 12 from 76 to get 64.
-16t^{2}+64=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
t=\frac{0±\sqrt{0^{2}-4\left(-16\right)\times 64}}{2\left(-16\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -16 for a, 0 for b, and 64 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
t=\frac{0±\sqrt{-4\left(-16\right)\times 64}}{2\left(-16\right)}
Square 0.
t=\frac{0±\sqrt{64\times 64}}{2\left(-16\right)}
Multiply -4 times -16.
t=\frac{0±\sqrt{4096}}{2\left(-16\right)}
Multiply 64 times 64.
t=\frac{0±64}{2\left(-16\right)}
Take the square root of 4096.
t=\frac{0±64}{-32}
Multiply 2 times -16.
t=-2
Now solve the equation t=\frac{0±64}{-32} when ± is plus. Divide 64 by -32.
t=2
Now solve the equation t=\frac{0±64}{-32} when ± is minus. Divide -64 by -32.
t=-2 t=2
The equation is now solved.