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Solve for h
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Solve for h (complex solution)
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\frac{12}{14.7}=e^{-0.0004h}
Divide both sides by 14.7.
\frac{120}{147}=e^{-0.0004h}
Expand \frac{12}{14.7} by multiplying both numerator and the denominator by 10.
\frac{40}{49}=e^{-0.0004h}
Reduce the fraction \frac{120}{147} to lowest terms by extracting and canceling out 3.
e^{-0.0004h}=\frac{40}{49}
Swap sides so that all variable terms are on the left hand side.
\log(e^{-0.0004h})=\log(\frac{40}{49})
Take the logarithm of both sides of the equation.
-0.0004h\log(e)=\log(\frac{40}{49})
The logarithm of a number raised to a power is the power times the logarithm of the number.
-0.0004h=\frac{\log(\frac{40}{49})}{\log(e)}
Divide both sides by \log(e).
-0.0004h=\log_{e}\left(\frac{40}{49}\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
h=\frac{\ln(\frac{40}{49})}{-0.0004}
Multiply both sides by -2500.