Solve 12+3{-6+2[5-(3-2)+5(7-8)]-5}

$$12 + 3 \{ - 6 + 2 [ 5 - ( 3 - 2 ) + 5 ( 7 - 8 ) ] - 5 \}$$

Evaluate

$$-27$$

Solution Steps

Subtract 2 from 3 to get 1.

$$12+3\left(-6+2\left(5-1+5\left(7-8\right)\right)-5\right)$$

Subtract 1 from 5 to get 4.

$$12+3\left(-6+2\left(4+5\left(7-8\right)\right)-5\right)$$

Subtract 8 from 7 to get -1.

$$12+3\left(-6+2\left(4+5\left(-1\right)\right)-5\right)$$

Multiply 5 and -1 to get -5.

$$12+3\left(-6+2\left(4-5\right)-5\right)$$

Subtract 5 from 4 to get -1.

$$12+3\left(-6+2\left(-1\right)-5\right)$$

Multiply 2 and -1 to get -2.

$$12+3\left(-6-2-5\right)$$

Subtract 2 from -6 to get -8.

$$12+3\left(-8-5\right)$$

Subtract 5 from -8 to get -13.

$$12+3\left(-13\right)$$

Multiply 3 and -13 to get -39.

$$12-39$$

Subtract 39 from 12 to get -27.

$$-27$$

Factor

$$-27$$