Solve 115^2-3^2+sqrt[5]{32}1-18+sqrt[3]{-8}

$$115 ^ { 2 } - 3 ^ { 2 } + \sqrt[ 5 ] { 32 } 1 - 18 + \sqrt[ 3 ] { - 8 }$$

Evaluate

$$13198$$

Solution Steps

Calculate 115 to the power of 2 and get 13225.

$$13225-3^{2}+\sqrt[5]{32}\times 1-18+\sqrt[3]{-8}$$

Calculate 3 to the power of 2 and get 9.

$$13225-9+\sqrt[5]{32}\times 1-18+\sqrt[3]{-8}$$

Subtract 9 from 13225 to get 13216.

$$13216+\sqrt[5]{32}\times 1-18+\sqrt[3]{-8}$$

Calculate \sqrt[5]{32} and get 2.

$$13216+2\times 1-18+\sqrt[3]{-8}$$

Multiply 2 and 1 to get 2.

$$13216+2-18+\sqrt[3]{-8}$$

Add 13216 and 2 to get 13218.

$$13218-18+\sqrt[3]{-8}$$

Subtract 18 from 13218 to get 13200.

$$13200+\sqrt[3]{-8}$$

Calculate \sqrt[3]{-8} and get -2.

$$13200-2$$

Subtract 2 from 13200 to get 13198.

$$13198$$

Factor

$$2\times 6599$$