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115=x^{2}-81
Consider \left(x+9\right)\left(x-9\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 9.
x^{2}-81=115
Swap sides so that all variable terms are on the left hand side.
x^{2}=115+81
Add 81 to both sides.
x^{2}=196
Add 115 and 81 to get 196.
x=14 x=-14
Take the square root of both sides of the equation.
115=x^{2}-81
Consider \left(x+9\right)\left(x-9\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 9.
x^{2}-81=115
Swap sides so that all variable terms are on the left hand side.
x^{2}-81-115=0
Subtract 115 from both sides.
x^{2}-196=0
Subtract 115 from -81 to get -196.
x=\frac{0±\sqrt{0^{2}-4\left(-196\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -196 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-196\right)}}{2}
Square 0.
x=\frac{0±\sqrt{784}}{2}
Multiply -4 times -196.
x=\frac{0±28}{2}
Take the square root of 784.
x=14
Now solve the equation x=\frac{0±28}{2} when ± is plus. Divide 28 by 2.
x=-14
Now solve the equation x=\frac{0±28}{2} when ± is minus. Divide -28 by 2.
x=14 x=-14
The equation is now solved.