Solve 115=xleft(1+3.10^-3.50right)

$$115 = x \left( 1+3. { 10 }^{ -3 } .50 \right)$$

Solve for x

$$x = \frac{230000}{2003} = 114\frac{1658}{2003} \approx 114.827758362$$

Steps for Solving Linear Equation

Calculate 10 to the power of -3 and get \frac{1}{1000}.

$$115=x\left(1+3\times \frac{1}{1000}\times 0.5\right)$$

Multiply 3 and \frac{1}{1000} to get \frac{3}{1000}.

$$115=x\left(1+\frac{3}{1000}\times 0.5\right)$$

Multiply \frac{3}{1000} and 0.5 to get \frac{3}{2000}.

$$115=x\left(1+\frac{3}{2000}\right)$$

Add 1 and \frac{3}{2000} to get \frac{2003}{2000}.

$$115=x\times \frac{2003}{2000}$$

Swap sides so that all variable terms are on the left hand side.

$$x\times \frac{2003}{2000}=115$$

Multiply both sides by \frac{2000}{2003}, the reciprocal of \frac{2003}{2000}.

$$x=115\times \frac{2000}{2003}$$

Multiply 115 and \frac{2000}{2003} to get \frac{230000}{2003}.

$$x=\frac{230000}{2003}$$