Solve 11y^2-98x-120=0

$$11 y ^ { 2 } - 98 x - 120 = 0$$

Solve for x

$$x=\frac{11y^{2}}{98}-\frac{60}{49}$$

Steps for Solving Linear Equation

Subtract 11y^{2} from both sides. Anything subtracted from zero gives its negation.

$$-98x-120=-11y^{2}$$

Add 120 to both sides.

$$-98x=-11y^{2}+120$$

The equation is in standard form.

$$-98x=120-11y^{2}$$

Divide both sides by -98.

$$\frac{-98x}{-98}=\frac{120-11y^{2}}{-98}$$

Dividing by -98 undoes the multiplication by -98.

$$x=\frac{120-11y^{2}}{-98}$$

Divide -11y^{2}+120 by -98.

$$x=\frac{11y^{2}}{98}-\frac{60}{49}$$

Solve for y (complex solution)

$$y=-\frac{\sqrt{1078x+1320}}{11}$$

$$y=\frac{\sqrt{1078x+1320}}{11}$$

Solve for y

$$y=\frac{\sqrt{1078x+1320}}{11}$$

$$y=-\frac{\sqrt{1078x+1320}}{11}\text{, }x\geq -\frac{60}{49}$$