Solve 11x^2+21+2x-y=3

$$11 x ^ { 2 } + 21 + 2 x - y = 3$$

Solve for y

$$y=11x^{2}+2x+18$$

Steps for Solving Linear Equation

Subtract 11x^{2} from both sides.

$$21+2x-y=3-11x^{2}$$

Subtract 21 from both sides.

$$2x-y=3-11x^{2}-21$$

Subtract 21 from 3 to get -18.

$$2x-y=-18-11x^{2}$$

Subtract 2x from both sides.

$$-y=-18-11x^{2}-2x$$

The equation is in standard form.

$$-y=-11x^{2}-2x-18$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{-11x^{2}-2x-18}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{-11x^{2}-2x-18}{-1}$$

Divide -18-11x^{2}-2x by -1.

$$y=11x^{2}+2x+18$$

Solve for x (complex solution)

$$x=\frac{\sqrt{11y-197}-1}{11}$$

$$x=\frac{-\sqrt{11y-197}-1}{11}$$

Solve for x

$$x=\frac{\sqrt{11y-197}-1}{11}$$

$$x=\frac{-\sqrt{11y-197}-1}{11}\text{, }y\geq \frac{197}{11}$$