Solve 119/10+31/20

$$11 \frac { 9 } { 10 } + 3 \frac { 1 } { 20 }$$

Evaluate

$$\frac{299}{20}=14.95$$

Solution Steps

Multiply 11 and 10 to get 110.

$$\frac{110+9}{10}+\frac{3\times 20+1}{20}$$

Add 110 and 9 to get 119.

$$\frac{119}{10}+\frac{3\times 20+1}{20}$$

Multiply 3 and 20 to get 60.

$$\frac{119}{10}+\frac{60+1}{20}$$

Add 60 and 1 to get 61.

$$\frac{119}{10}+\frac{61}{20}$$

Least common multiple of 10 and 20 is 20. Convert \frac{119}{10} and \frac{61}{20} to fractions with denominator 20.

$$\frac{238}{20}+\frac{61}{20}$$

Since \frac{238}{20} and \frac{61}{20} have the same denominator, add them by adding their numerators.

$$\frac{238+61}{20}$$

Add 238 and 61 to get 299.

$$\frac{299}{20}$$

Factor

$$\frac{13 \cdot 23}{2 ^ {2} \cdot 5} = 14\frac{19}{20} = 14.95$$