Solve 108[3-2*108(1+x)]=0

$$108 [ 3 - 2 \cdot 108 ( 1 + x ) ] = 0$$

Solve for x

$$x=-\frac{71}{72}\approx -0.986111111$$

Steps for Solving Linear Equation

Divide both sides by 108. Zero divided by any non-zero number gives zero.

$$3-2\times 108\left(1+x\right)=0$$

Multiply 2 and 108 to get 216.

$$3-216\left(1+x\right)=0$$

Use the distributive property to multiply -216 by 1+x.

$$3-216-216x=0$$

Subtract 216 from 3 to get -213.

$$-213-216x=0$$

Add 213 to both sides. Anything plus zero gives itself.

$$-216x=213$$

Divide both sides by -216.

$$x=\frac{213}{-216}$$

Reduce the fraction \frac{213}{-216} to lowest terms by extracting and canceling out 3.

$$x=-\frac{71}{72}$$