Solve 1024=-16t^2+1024

$$1024 = - 16 t ^ { 2 } + 1024$$

Solve for t

$$t=0$$

Steps by Finding Square Root

Swap sides so that all variable terms are on the left hand side.

$$-16t^{2}+1024=1024$$

Subtract 1024 from both sides.

$$-16t^{2}=1024-1024$$

Subtract 1024 from 1024 to get 0.

$$-16t^{2}=0$$

Divide both sides by -16. Zero divided by any non-zero number gives zero.

$$t^{2}=0$$

Take the square root of both sides of the equation.

$$t=0 t=0$$

The equation is now solved. Solutions are the same.

$$t=0$$

Steps Using the Quadratic Formula

Swap sides so that all variable terms are on the left hand side.

$$-16t^{2}+1024=1024$$

Subtract 1024 from both sides.

$$-16t^{2}[phone]=0$$

Subtract 1024 from 1024 to get 0.

$$-16t^{2}=0$$

Divide both sides by -16. Zero divided by any non-zero number gives zero.

$$t^{2}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$t=\frac{0±\sqrt{0^{2}}}{2}$$

Take the square root of 0^{2}.

$$t=\frac{0±0}{2}$$

Divide 0 by 2.

$$t=0$$