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2^{n-1}=1024
Swap sides so that all variable terms are on the left hand side.
\log(2^{n-1})=\log(1024)
Take the logarithm of both sides of the equation.
\left(n-1\right)\log(2)=\log(1024)
The logarithm of a number raised to a power is the power times the logarithm of the number.
n-1=\frac{\log(1024)}{\log(2)}
Divide both sides by \log(2).
n-1=\log_{2}\left(1024\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
n=10-\left(-1\right)
Add 1 to both sides of the equation.