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\left(10z+1\right)\left(100z^{2}-10z+1\right)
Rewrite 1000z^{3}+1 as \left(10z\right)^{3}+1^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right). Polynomial 100z^{2}-10z+1 is not factored since it does not have any rational roots.