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8\left(125+w^{9}\right)
Factor out 8.
\left(w^{3}+5\right)\left(w^{6}-5w^{3}+25\right)
Consider 125+w^{9}. Rewrite 125+w^{9} as \left(w^{3}\right)^{3}+5^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
8\left(w^{3}+5\right)\left(w^{6}-5w^{3}+25\right)
Rewrite the complete factored expression. The following polynomials are not factored since they do not have any rational roots: w^{3}+5,w^{6}-5w^{3}+25.