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-x^{2}+100x-2100=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-100±\sqrt{100^{2}-4\left(-1\right)\left(-2100\right)}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 100 for b, and -2100 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-100±\sqrt{10000-4\left(-1\right)\left(-2100\right)}}{2\left(-1\right)}
Square 100.
x=\frac{-100±\sqrt{10000+4\left(-2100\right)}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{-100±\sqrt{10000-8400}}{2\left(-1\right)}
Multiply 4 times -2100.
x=\frac{-100±\sqrt{1600}}{2\left(-1\right)}
Add 10000 to -8400.
x=\frac{-100±40}{2\left(-1\right)}
Take the square root of 1600.
x=\frac{-100±40}{-2}
Multiply 2 times -1.
x=-\frac{60}{-2}
Now solve the equation x=\frac{-100±40}{-2} when ± is plus. Add -100 to 40.
x=30
Divide -60 by -2.
x=-\frac{140}{-2}
Now solve the equation x=\frac{-100±40}{-2} when ± is minus. Subtract 40 from -100.
x=70
Divide -140 by -2.
x=30 x=70
The equation is now solved.
-x^{2}+100x-2100=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
-x^{2}+100x-2100-\left(-2100\right)=-\left(-2100\right)
Add 2100 to both sides of the equation.
-x^{2}+100x=-\left(-2100\right)
Subtracting -2100 from itself leaves 0.
-x^{2}+100x=2100
Subtract -2100 from 0.
\frac{-x^{2}+100x}{-1}=\frac{2100}{-1}
Divide both sides by -1.
x^{2}+\frac{100}{-1}x=\frac{2100}{-1}
Dividing by -1 undoes the multiplication by -1.
x^{2}-100x=\frac{2100}{-1}
Divide 100 by -1.
x^{2}-100x=-2100
Divide 2100 by -1.
x^{2}-100x+\left(-50\right)^{2}=-2100+\left(-50\right)^{2}
Divide -100, the coefficient of the x term, by 2 to get -50. Then add the square of -50 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-100x+2500=-2100+2500
Square -50.
x^{2}-100x+2500=400
Add -2100 to 2500.
\left(x-50\right)^{2}=400
Factor x^{2}-100x+2500. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-50\right)^{2}}=\sqrt{400}
Take the square root of both sides of the equation.
x-50=20 x-50=-20
Simplify.
x=70 x=30
Add 50 to both sides of the equation.