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\left(10a^{2}-3x\right)\left(10a^{2}+3x\right)
Rewrite 100a^{4}-9x^{2} as \left(10a^{2}\right)^{2}-\left(3x\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).
\left(-3x+10a^{2}\right)\left(3x+10a^{2}\right)
Reorder the terms.