Solve 10x^2-33x+c=0

$$10 x ^ { 2 } - 33 x + c = 0$$

Solve for c

$$c=-x\left(10x-33\right)$$

Solution Steps

Subtract 10x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-33x+c=-10x^{2}$$

Add 33x to both sides.

$$c=-10x^{2}+33x$$

Solve for x (complex solution)

$$x=\frac{\sqrt{1089-40c}+33}{20}$$

$$x=\frac{-\sqrt{1089-40c}+33}{20}$$

Solve for x

$$x=\frac{\sqrt{1089-40c}+33}{20}$$

$$x=\frac{-\sqrt{1089-40c}+33}{20}\text{, }c\leq \frac{1089}{40}$$