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a+b=37 ab=10\times 33=330
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as 10w^{2}+aw+bw+33. To find a and b, set up a system to be solved.
1,330 2,165 3,110 5,66 6,55 10,33 11,30 15,22
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 330.
1+330=331 2+165=167 3+110=113 5+66=71 6+55=61 10+33=43 11+30=41 15+22=37
Calculate the sum for each pair.
a=15 b=22
The solution is the pair that gives sum 37.
\left(10w^{2}+15w\right)+\left(22w+33\right)
Rewrite 10w^{2}+37w+33 as \left(10w^{2}+15w\right)+\left(22w+33\right).
5w\left(2w+3\right)+11\left(2w+3\right)
Factor out 5w in the first and 11 in the second group.
\left(2w+3\right)\left(5w+11\right)
Factor out common term 2w+3 by using distributive property.
w=-\frac{3}{2} w=-\frac{11}{5}
To find equation solutions, solve 2w+3=0 and 5w+11=0.
10w^{2}+37w+33=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
w=\frac{-37±\sqrt{37^{2}-4\times 10\times 33}}{2\times 10}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 10 for a, 37 for b, and 33 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
w=\frac{-37±\sqrt{1369-4\times 10\times 33}}{2\times 10}
Square 37.
w=\frac{-37±\sqrt{1369-40\times 33}}{2\times 10}
Multiply -4 times 10.
w=\frac{-37±\sqrt{1369-1320}}{2\times 10}
Multiply -40 times 33.
w=\frac{-37±\sqrt{49}}{2\times 10}
Add 1369 to -1320.
w=\frac{-37±7}{2\times 10}
Take the square root of 49.
w=\frac{-37±7}{20}
Multiply 2 times 10.
w=-\frac{30}{20}
Now solve the equation w=\frac{-37±7}{20} when ± is plus. Add -37 to 7.
w=-\frac{3}{2}
Reduce the fraction \frac{-30}{20} to lowest terms by extracting and canceling out 10.
w=-\frac{44}{20}
Now solve the equation w=\frac{-37±7}{20} when ± is minus. Subtract 7 from -37.
w=-\frac{11}{5}
Reduce the fraction \frac{-44}{20} to lowest terms by extracting and canceling out 4.
w=-\frac{3}{2} w=-\frac{11}{5}
The equation is now solved.
10w^{2}+37w+33=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
10w^{2}+37w+33-33=-33
Subtract 33 from both sides of the equation.
10w^{2}+37w=-33
Subtracting 33 from itself leaves 0.
\frac{10w^{2}+37w}{10}=-\frac{33}{10}
Divide both sides by 10.
w^{2}+\frac{37}{10}w=-\frac{33}{10}
Dividing by 10 undoes the multiplication by 10.
w^{2}+\frac{37}{10}w+\left(\frac{37}{20}\right)^{2}=-\frac{33}{10}+\left(\frac{37}{20}\right)^{2}
Divide \frac{37}{10}, the coefficient of the x term, by 2 to get \frac{37}{20}. Then add the square of \frac{37}{20} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
w^{2}+\frac{37}{10}w+\frac{1369}{400}=-\frac{33}{10}+\frac{1369}{400}
Square \frac{37}{20} by squaring both the numerator and the denominator of the fraction.
w^{2}+\frac{37}{10}w+\frac{1369}{400}=\frac{49}{400}
Add -\frac{33}{10} to \frac{1369}{400} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(w+\frac{37}{20}\right)^{2}=\frac{49}{400}
Factor w^{2}+\frac{37}{10}w+\frac{1369}{400}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(w+\frac{37}{20}\right)^{2}}=\sqrt{\frac{49}{400}}
Take the square root of both sides of the equation.
w+\frac{37}{20}=\frac{7}{20} w+\frac{37}{20}=-\frac{7}{20}
Simplify.
w=-\frac{3}{2} w=-\frac{11}{5}
Subtract \frac{37}{20} from both sides of the equation.
x ^ 2 +\frac{37}{10}x +\frac{33}{10} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 10
r + s = -\frac{37}{10} rs = \frac{33}{10}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -\frac{37}{20} - u s = -\frac{37}{20} + u
Two numbers r and s sum up to -\frac{37}{10} exactly when the average of the two numbers is \frac{1}{2}*-\frac{37}{10} = -\frac{37}{20}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-\frac{37}{20} - u) (-\frac{37}{20} + u) = \frac{33}{10}
To solve for unknown quantity u, substitute these in the product equation rs = \frac{33}{10}
\frac{1369}{400} - u^2 = \frac{33}{10}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = \frac{33}{10}-\frac{1369}{400} = -\frac{49}{400}
Simplify the expression by subtracting \frac{1369}{400} on both sides
u^2 = \frac{49}{400} u = \pm\sqrt{\frac{49}{400}} = \pm \frac{7}{20}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-\frac{37}{20} - \frac{7}{20} = -2.200 s = -\frac{37}{20} + \frac{7}{20} = -1.500
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.